<em>Question:</em>
<em>Abraham has visited at least 50 countries; he plans to visit five new countries per year (Y) for the next several years. Which inequality and solution shows the amount of years they will take for Abraham to meet his goal.</em>
Answer:
Step-by-step explanation:
Given
------ at least
Required
Represent as an inequality
"at least" means 
So the countries he has visited can be represented as thus;
If
1 year = 5 countries
y years would be 5y countries
So, in y years; he'd have visited
To determine the value of y.
We have that
<em>in the world</em>
<em>Substitute 195 for Countries</em>
<em>Collect Like Terms</em>
<em>Divide through by 5</em>
<em>Reorder</em>
This means that; he'll visit all countries in at most 29 years' time
Answer:
141.2/175.8=.803185
1-.803185=.1968=20% markdown
ples give brainliest! :D
Answer: 30
Step-by-step explanation:
21+39/2
=30
This problem can be solved from first principles, case by case. However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.
Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected
Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}
Therefore the
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}
