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Anon25 [30]
3 years ago
12

PLEASE HELP find value of x and y

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0

<u>Given</u><u> </u><u>:</u><u> </u>

  • There is a quadrilateral.
  • Two sides of the quadrilateral are parallel .
  • Four angles are 96° , 2x° , 94° & ( 3y + 44 )°.

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x & y .

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Here , 96° & 2x° are co - interior angles and we know that the sum of co - Interior angles is 180°.

⇒ 96° + 2x = 180° .

⇒ 2x = 180° - 96° .

⇒ 2x = 84° .

⇒ x = \red{\sf \dfrac{84^{\circ}}{2}}

\bf\longmapsto x = 42^{\circ}

<u>Hence</u><u> </u><u>value</u><u> </u><u>of </u><u>x</u><u> </u><u>is</u><u> </u><u>4</u><u>2</u><u>°</u><u> </u><u>.</u>

Similarly , 94° & ( 3y + 44) ° are co- interior angles

⇒ 94° + ( 3y + 44)° = 180° .

⇒ ( 3y + 44 )° = 180° - 94° .

⇒ 3y + 44° = 86°.

⇒ 3y = 86° - 44° .

⇒ 3y = 42° .

⇒ y = \sf \red{\dfrac{42^{\circ}}{3}}

\bf\longmapsto y = 14^{\circ}

<u>Hence</u><u> </u><u>the </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>is</u><u> </u><u>1</u><u>4</u><u>°</u><u>.</u>

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