Question

PLEASE HELP find value of x and y

Answer 1

Given :

• There is a quadrilateral.
• Two sides of the quadrilateral are parallel .
• Four angles are 96° , 2x° , 94° & ( 3y + 44 )°.

To Find :-

• The value of x & y .

Solution :-

Here , 96° & 2x° are co - interior angles and we know that the sum of co - Interior angles is 180°.

⇒ 96° + 2x = 180° .

⇒ 2x = 180° - 96° .

⇒ 2x = 84° .

⇒ x = $\red{\sf \dfrac{84^{\circ}}{2}}$

$\bf\longmapsto x = 42^{\circ}$

Hence value of x is 42° .

Similarly , 94° & ( 3y + 44) ° are co- interior angles

⇒ 94° + ( 3y + 44)° = 180° .

⇒ ( 3y + 44 )° = 180° - 94° .

⇒ 3y + 44° = 86°.

⇒ 3y = 86° - 44° .

⇒ 3y = 42° .

⇒ y = $\sf \red{\dfrac{42^{\circ}}{3}}$

$\bf\longmapsto y = 14^{\circ}$

Hence the value of y is 14°.