Answer:
Step-by-step explanation:
In this question, the sample space contains 8 elements and has been given as;
HHT HHH THH HTH HTT TTT TTH THT
1. For event A:
Outcomes of alternating tail and head = THH HTH HTT THT
= 4 outcomes
Pr(alternating tail and head (with either coming first)) = 
= 
2. For event B:
Outcomes of no tails on the first two tosses = HHT HHH
= 2 outcomes
Pr (No tails on the first two tosses) = 
= 
For event C:
Outcomes of a tail on both the first and the last tosses = THT TTT
= 2 outcomes
Pr(A tail on both the first and last tosses) = 
= 
Y = -2x + 4
The graph of the equation is the set of points that are solutions to the
equation.
The equation 2x + y = 4 is represented by the same graph.
For point (1, 2): 2 = -2(1) + 4 = -2 + 4 = 2.
Therefore, the point (1, 2) lies on the the graph of the equation.
For the
point (0, 2): 2 ≠ -2(0) + 4 = 0 + 4 = 4.
Therefore, the point (0, 2) DOES NOT lie on the graph of the equation.
Answer:
The answer is B. 1/3
Step-by-step explanation:
Hope this helps! :)
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3. B
Hope this helps ..........................