A 5 kg box is sliding across a level floor. The box is acted upon by a force of 27 newtons east and a frictional force of 17 new
1 answer:
Answer:
The acceleration of the box is 2.
Explanation:
According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.
Net force = Mass × Acceleration
So
Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.
Net force = 27-17 = 10 N.
Thus,
So 2 is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.
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- Yes
Answer:
In statics condition and if is a body is over plane surface N = mg
In all cases which a body is on a ramp force N will be smaller than mg, and depending on the level of the ramp (bigger the ramp smaller force N)
Explanation:
See annex (Figure 1)
We can see with the help of force diagram the relation between N force and mg
Lets look first the body on the ramp assuming there is not movement
The sum of forces alog y axis = 0
mg* cos∠ BAC = N (normal force)
So N is always a fuction of mg and of the cosine of the inclination angle, and the cosine of angle varies from value 1 when the angle is 0 (look the case where the block is on the surface without inclination N = mg ).
And as the inclination increase the value of cosine will become smaller and so will N force which is directly proportional of cosine of the inclination angle
Therefore we can say that force N is always minor than mg unless in extreme case where the block is over the surface in which case N takes its maximum value N = mg
