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UNO [17]
3 years ago
11

QUESTION 5 of 10: You are considering selling your home. You consult with an agent who gives you the asking prices of five homes

(comps)
in your area: $165,000, $188,000, $175,000, $150,000 and $400,000. The $400,000 is an outlier so you will not include it in your evaluation. In
determining a reasonable asking price, what is the mean of the four remaining comps?
a) $188,000
b) $215,000
Oc) $169,500
d) $175,000
Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

Answer: $169,500

Step-by-step explanation:

The mean simply means the average price of a set of a numbers that are given. For one t calculate the mean, one has to add the numbers that are given and then divide them by the amount of numbers.

I'm the case above, the numbers given are $165,000, $188,000, $175,000, and $150,000.

Mean = ($165,000 ,+ $188,000 +$175,000 + $150,000) ÷ 4

= $678,000/4

= $169,500

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In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

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A taxi driver charges a flat rate of $3.25 plus an additional $0.75 per mile. If Amanda has, at most, $70 for a cab ride, how fa
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Answer : Amanda can go 89 miles with the 70 dollars she has

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A fraction equal to one for the relationship between these units m/c=1
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\dfrac{m}{c}=1\ \text{therefore}\ m=c\ and\ m,c\neq0

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Answer:

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Step-by-step explanation:

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