2x+y=9
3x+5y=19
I will do this problem in 2 ways. I.)Substitution II.)Elimination
Solution I.) Substitution
We can subtract 2x from both sides in the first equation.
y=9-2x
Now we can substitute the y in the second equation with 9-2x
3x+5(9-2x)=19
-7x+45=19
-7x=-26
x=26/7
y=9-2(26/7)=11/7
Solution II.)Elimination
We can multiply both side of first equation by 5 to get a 5y in both equations.
10x+5y=45
Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.
(10x+5y)-(3x+5y)=45-19
7x=26
x=26/7
2*26/7+y=9
y=11/7
Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.
Step-by-step explanation:
For the quadratic equation to have 1 repeated real solution, the discriminant b² - 4ac must be zero.
=> (-z)² - 4(z - 5)(5) = 0
=> z² - 20(z - 5) = 0
=> z² - 20z + 100 = 0
=> (z - 10)² = 0
Therefore z = 10.
Answer:y=2/3x-10/3
- 4/-6 is 4/6 so m is 4/6 then fill in the x and y variables in y=Mx+b solve for b then start plotting the equation of the line to check and you get your answer
I think this is the answer you might need to check again with more people
Answer:
20x²+180x + 405
Step-by-step explanation:
Follow PEMDAS to know what you do first
square (2x + 9) by foiling
(2x+9) (2x + 9)
= 4x²+ 36x + 81
Multiply by 5
20x²+180x + 405
Determine the power by looking at the numerator of the exponent.
Determine the root by looking at the denominator of the exponent.
Using the base as the radicand, raise the radicand to the power and use the root as the index.
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