How many solutions does this quadratic equation have?
6p^2-7p+5=0
2 answers:
Answer:
No Real soultions
Step-by-step explanation:
solve by using the discriminant
b^2-4ac
(-7)^2 - 4 x 6 x 5
= -71
negative--->-71<0 no real solution
Answer:
It has no real solution.
Step-by-step explanation:
6p^2 − 7p + 5 = 0
For this equation: a = 6, b = -7, c = 5
6p^2+ −7p + 5 = 0
Step 1: Use quadratic formula with a=6, b=-7, c=5.
p = -b ± √b^2 - 4ac/2a
p = -(-7) ± √(-7)^2 - 4(6)(5)/2(6)
p = 7 ± √-71/12
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