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Usimov [2.4K]
3 years ago
11

How many solutions does this quadratic equation have? 6p^2-7p+5=0

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
4 0

Answer:

No Real soultions

Step-by-step explanation:

solve by using the discriminant

b^2-4ac

(-7)^2 - 4 x 6 x 5

= -71

negative--->-71<0  no real solution

KatRina [158]3 years ago
3 0

Answer:

It has no real solution.

Step-by-step explanation:

6p^2 − 7p + 5 = 0

For this equation: a = 6, b = -7, c = 5

6p^2+ −7p + 5 = 0

Step 1: Use quadratic formula with a=6, b=-7, c=5.

p = -b ± √b^2 - 4ac/2a

p = -(-7) ± √(-7)^2 - 4(6)(5)/2(6)

p = 7 ± √-71/12

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Step-by-step explanation:

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Figure B has the larger volume.

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<em>Additional comment</em>

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HELP PRECALC DO NOT UNDERSTAND WILL GIVE BRAINLIEST
Olegator [25]

Answer:

  the lower right matrix is the third correct choice

Step-by-step explanation:

Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).

Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.

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We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.

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