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Semmy [17]
3 years ago
6

If 50 milliliters of a liquid are poured from a graduated cylinder into a container with a different shape, how much liquid will

be in the second container
A.100 milliliters
B.50 milliliters
C.25 milliliters
D.12.5 milliliters
Mathematics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

B, 50 milliliters.

Step-by-step explanation:

No matter the shape of the container, if no liquid is removed from the first container, or on its way into the second container, the same amount of liquid will remain.

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How do you explain how to get h(t)=7(t-25)
Nutka1998 [239]
Hey There! :)

To Solve for t.
h(t)=7(t-25)
Distribute the brackets.
h(t)=7*t-7*25
h(t)=7t-175
Subtract 7t from both sides.
(h(t))-7t=(7t-175)-7t
(h(t)-7t=-175
h*t-7t=-175
Factor out variable, t.
t(h-7)=-175
Divide both sides by h-7.
(t(h-7))/h-7=(-175)/h-7
t=-175/h-7

Hope this helps!
-Benjamin




8 0
3 years ago
A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
3 years ago
Round 129.392 to the nearest ten,one,tenth,and hundredth. I need help plz
Soloha48 [4]
Nearest ten=130
nearest one=129
nearest tenth= 129.4
nearest hundredth= 129.39
8 0
3 years ago
Use this figure to find value of FOD
stepladder [879]
Hey there!

BOD is a 90 degrees angle. Make an equation for that angle. 15+12+x=90. Simplify this to 27+x=90. You need to isolate x, so subtract 27 on each side to get x=63. C is the answer.

I hope this helps!
4 0
3 years ago
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Kim earned $96 babysitting for 12 hours. how much did she earn each hour
lianna [129]

Answer:

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Step-by-step explanation:

96 divided by 12 is 8

:)))))

7 0
3 years ago
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