Answer:
Average velocity of the function over the given interval
= 
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given function y = 3/x -2 ...(i)
The average velocity of the function over the given interval
Average velocity = 
= 
now integrating
= 
= 
= 
by using formulas
log a-log b = log(a/b)
on simplification , we get
= 
= 
Average velocity of the function over the given interval
= 
Use the 2 points to find the gradient of the line
Gradient = (y - y1)/(x - x1), y and y1 are the two different y values.
(2.3 - - 7.4)/(-4.3 - 1.3) = -97/56 = -1.732
Note: y and x both come from the same coordinate, and y1 and x1 also come from the same coordinates - (x , y), (x1 , y1)
Use the following to find the equation (x, x1, y, and y1 are not the same as the first part)
y - y1 = m(x - x1)
Where x2 and y2 is an intersection (one of the coordinates you used) and m is the gradient you found.
So...
y - 2.3 = -1.732(x - - 4.3)
You can simplify this if you are required to.
Answer:
7.
Solution given;
male=15
female=27
1st term=5*3
2nd term=3*3*3
now
Highest common factor=3
So
<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>
<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>
Answer
B)
Step by step explanation
The standard form of circle when center(h, k) and radius r, given is
(x - h)^2 + (y - k)^2 = r^2
Given: (h, k) = (5, 0) and r = 3
Now plug in these values in the standard form, we get
(x - 5)^2 + (y - 0)^2 = 3^2

Therefore, the answer is B) 
Thank you :)
12:7
because you add 7 and 5 and then there is the 7 for the book weight