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3 years ago

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In a certain clothing store, 6 shirts and 3 ties cost $79.50, and 3 shirts and 2 ties cost $41. Determine the cost of each shirt

.

1 answer:

Pepsi [2]3 years ago

7 0

Answer: $12

Step-by-step explanation:

For this problem, we can use system of equations to solve. Let's use x for shirts and y for ties.

Equation 1

6x+3y=79.5

This equation comes from the first sentence. 79.5 is the total cost.

Equation 2

3x+2y=41

This equation comes from the second part of the first sentence. 41 is the total cost.

Since we are looking for the cost of each shirt, let's use the elimination method to eliminate y. First, we need to multiply both equations to that the y in both equations equal each other.

2(6x+3y=79.5)

3(3x+2y=41)

Now that we have chosen a common number, we can multiply.

12x+6y=159

9x+6y=123

We can now subtract both equations to cancel out y.

3x=36

Divide to get x alone.

x=12

Each shirt costs $12.

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Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

7 0

3 years ago

A 40 foot ladder is set against the side of a house so that it reaches up 24 feet. If Aiden grabs the ladder at its base and pul

Nataly [62]

Answer:12

Step-by-step explanation:

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3 years ago

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot.

Step2247 [10]

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

$m\angle O+m\angle P+m\angle Q=180^\circ$ [Angle sum property]

$26^\circ+m\angle P+90^\circ=180^\circ$

$m\angle P+116^\circ=180^\circ$

$m\angle P=180^\circ -116^\circ$

$m\angle P=64^\circ$

According to Law of Sines, we get

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

Using the Law of Sines, we get

$\dfrac{p}{\sin P}=\dfrac{o}{\sin O}$

$\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}$

Substituting the given values, we get

$\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}$

$\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}$

$\dfrac{4.9}{0.89879}\times 0.43837=PQ$

$2.38989=PQ$

Approximate the value to the nearest tenth of a foot.

$PQ\approx 2.4$

Therefore, the length of PQ is 2.4 ft.

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A coordinate plane with a straight line passing through the points (negative 6, negative 8) and (2, 8).

gizmo_the_mogwai [7]

Answer:

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Step-by-step explanation:

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mash [69]

Answer:

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Step-by-step explanation:

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