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2 years ago

Find the value of the variables

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

8 0

Answer:

x = 15

y = 12

z = 20

Step-by-step explanation:

For right angle x^2 + z^2 = (9 + 16)^2 => x^2 + z^2 = 625

then z^2 = y^2 + 16^2 => y^2 = z^2 - 256

and x^2 = y^2 + 9^2 => y^2 = x^2 - 81

so z^2 - 256 = x^2 - 81

z^2 = x^2 + 175

replace z^2 = x^2 + 175 into the first equation

x^2 + (x^2 + 175) = 625

2x^2 = 450

x^2 = 225

x = 15

If x = 15 => 15^2 + z^2 = 625 => z^2 = 400 => z = 20

y^2 = z^2 - 256 => y^2 = 400 - 256 = 144

then y = 12

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yuradex [85]

Answer:

48 cm²

Step-by-step explanation:

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3 years ago

You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop

Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

$P(A) = 0.99*0.1 + 0.9*0.9 = 0.909$

What is the probability that this person has the flu?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11$

The correct answer is:

E. 0.11

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3 years ago

QT 1.

erma4kov [3.2K]

1: 3.2
2: B. 1.6
3: C. 6.4
4: D. 17.92

I'm unable to see the table for 5, are you able to attach it?

5 0

3 years ago

Solve for the following equation<br><br> 9/4x + 1/3 = 5/2x

marshall27 [118]

Answer:

3/4

Step-by-step explanation:

plug values in for x till you get it right

7 0

2 years ago

A scientist is growing bacteria in a lab for study. One particular type of bacteria grows at a rate of y=2t^2+3t+500. A differen

Leya [2.2K]

ANSWER

Approximately after 15 minutes.

EXPLANATION

The growth rate of the first bacteria is

$y = 2 {t}^{2} + 3t + 500$

The growth rate of the first bacteria :

$y = 3 {t}^{2} + t + 300$

To find the time that, there will be an equal number of bacteria, we equate the two equation;

$3 {t}^{2} + t + 300 = 2 {t}^{2} + 3t + 500$

$3 {t}^{2} - 2 {t}^{2} + t - 3t + 300 - 500 =00$

${t}^{2} - 2t - 200= 0$

We solve for t to get,

$t = 15.177$

$t = - 13.177$

We discard the negative value.

This implies that,

$t \approx15$

8 0

4 years ago

Find the value of the variables ​

Find the value of the variables