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kykrilka [37]
3 years ago
10

Why are arithmetic sequences discrete data?

Mathematics
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

A sequence is a discrete structure used to represent an ordered list.

Step-by-step explanation:

Discrete values are values between the terms if the sequences are not included in the sequence. If you collect all the terms of the sequence into a set, that set will always be discrete, because there's only countably many of them, and every interval is uncountable. So in that sense, yes, sequences are discrete. A sequence is a discrete structure used to represent an ordered list. A sequence is a function from a subset of the set of integers (usually either the set {0,1,2,. . .} or {1,2, 3,. . .}to a set S. We use the notation an to denote the image of the integer n. We call an a term of the sequence.

schepotkina [342]3 years ago
3 0

Answer:

If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence.

Step-by-step explanation:

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Which property of multiplication is shown? 3 * (5 * 7) = (3 * 5) * 7
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3 years ago
The data for Shawn's phone has 32000 megabytes if storage for photos . She wants to increase the amount by 4% if each photo uses
Law Incorporation [45]

Answer:

Yes, she will have have enough new memory for 200 additional photos.

Step-by-step explanation:

Given:

Initial memory for storage, M_{o}=32000\textrm{ megabytes}

Increase in memory =4%

Therefore, increase in memory, \Delta M=\frac{4}{100}\times 32000=1280\textrm{ megabytes}

Now, memory consumed by 1 photo = 5 megabytes

So, memory consumed by 200 additional photos = 200\times 5=1000\textrm{ megabytes}

Memory left in her phone = 1280 - 1000 = 280 megabytes

Therefore, she will have additional 280 megabytes of memory left in her phone.

As memory consumed by 200 additional photos is less than that of the increase in memory, therefore, she does have enough new memory for 200 additional photos.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%284y%20%2B%204x%29%20%3D%20" id="TexFormula1" title="(4y + 4x) = " alt="(4y + 4x) = " align="
Semmy [17]
<span> Simplifying
4x + 4y = 0

 Solving
4x + 4y = 0

 Solving for variable 'x'.
 Move all terms containing x to the left, all other terms to the right.

 Add '-4y' to each side of the equation.
4x + 4y + -4y = 0 + -4y

 Combine like terms:
4y + -4y = 0
4x + 0 = 0 + -4y
4x = 0 + -4y

 Remove the zero:
4x = -4y

 Divide each side by '4'.
x = -1y

 Simplifying
x = -1y</span>
8 0
4 years ago
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