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butalik [34]
3 years ago
14

Refer to the figure below to complete the following problem.

Mathematics
1 answer:
Ratling [72]3 years ago
4 0
Im pretty sure the answer id b
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Hfejfndsljrogldfmvdf gffhelppp
LuckyWell [14K]

Answer:

c

Step-by-step explanation:

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3 years ago
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If the flare is launched with an initial velocity of 144 feet per second, find the height after 2 seconds. The answer is not 288
Rashid [163]
H= ut -16 t^2

h = 144(2) - 16 (4)

= 288 - 64 = 224
4 0
3 years ago
How to solve linear equations in slope intercept form<br> y=-x+2
alexdok [17]
Slope intercept from is y=mx+b  so y= a -xor a -1x + 2
.
so y is y.
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the +2 means you will move up or to the right by 2 units

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3 years ago
Whats the answer and how do you work it out?<br>5/12-1/4​
Sergio [31]

Answer:

\frac{5}{12}  -  \frac{1}{4}  \frac{ \times }{ \times }  \frac{3}{ 3 }  \\  \frac{5}{12}  -  \frac{3}{12}  \\  =  \frac{2}{12}  =  \frac{1}{6}

4 0
3 years ago
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Divide the polynomial x^3+x^2-2x+3 by (x-1)​
Anni [7]

Answer:

x² + 2x + (3 / (x − 1))

Step-by-step explanation:

Start by setting up the division:

.........____________

x − 1 | x³ + x² − 2x + 3

Start with the first term, x³.  Divided by x, that's x².  So:

.........____x²______

x − 1 | x³ + x² − 2x + 3

Multiply x − 1 by x², subtract the result, and drop down the next term:

.........____x²______

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Repeat the process over again.  First term is 2x².  Divided by x is 2x.  So:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Multiply, subtract the result, and drop down the next term:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

.................-(2x² − 2x)

.................---------------

.....................................3

x doesn't divide into 3, so that's the remainder.

Therefore, the answer is:

x² + 2x + (3 / (x − 1))

8 0
3 years ago
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