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ella [17]
3 years ago
5

Express 6^1/4 b^3/4 c^1/4 using a radical

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

Answer:

B

Step-by-step explanation:

6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}

so answer is B

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anygoal [31]

8 ÷ (7 - 9) * ( 4 + (-4) ) <--- notice that bolded part.

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3 years ago
U(8, 9) and V(2, 5) are the endpoints of a line segment. What is the midpoint M of that line segment?
Crazy boy [7]

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Given 2 points (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

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3 years ago
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Answer:

We conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.

Step-by-step explanation:

Given the expression

y = 2x² + 3x

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y = 2(0)² + 3(0)

y = 0+0

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Thus, the ordered pair is: (0, 0)

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Thus, the ordered pair is: (-2, 2)

Therefore, we conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.

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