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3 years ago

Please help me with this! If you’re smart you can solve it!

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

5 0

Let L, H, W be the length, height, and width.

Using the 3 clues they gave us, we have:

L x W = 12

L x H = 8

W x H = 6

Our goal is to figure out volume: L x W x H

One way of solving this is to just randomly plug in numbers which should be easy to do for this problem.

Another way is to use substitution.

From first equation: L = 12/W

Plug that into second equation:

12/W x H = 8,

H = (8/12)W = (2/3)W

Plug that into the third equation:

W x (2/3)W = 6,

W x W = 9

W must be equal to 3.

And since we know that L x H = 8

Then L x H x W = (8) x 3 = 24 cm^3

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Are the lines 2y - x = 6 and 6x - 3y - 33 = 0 parallel, perpendicular, or neither?

nirvana33 [79]

Hello there!
The lines 2y - x = 6 and 6x - 3y - 33 = 0 are Neither <span>parallel nor perpendicular.
They are intersecting lines. So, the answer is Neither.
I hope this helps!</span>

7 0

3 years ago

Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0

3 years ago

Find slope of line (1,2) and (2,5) <br> Write equation and final answer

sdas [7]

Equation: y = 3x
Final Answer: 3

3 0

3 years ago

If f(x)= 1/3x and g(x)=3x, then what are g * f (x) and g*f(1/2)

MrMuchimi

The correct answer is: 3) " x ; 1/2" .
_____________________________________________________
Explanation:
_____________________________________________________
Question 1)

g [ f(x) ] = ? ;

→ Given: " f(x) = 1/3 x " ;

→ Given: " g(x) = 3x " ;
__________________________________
g [ f(x) ] = g(1/3 x) = 3(1/3 x) = 1x = "x" .
__________________________________
Question 2)

g [ f(1/2) ] = ? ;
__________________________________
→ Given: " f(x) = 1/3 x " ;

→ f(1/2) = (1/3) * (1/2) = (1*1) / (3*2) = (1/6) ;

→ g [ f(x) ] =

g(1/6) = 3* (1/6) = (3/1) * (1/6) = (3*1) / (1*6) = 3/6 = (3÷3) / (6÷3) = " 1/2 " .
___________________________________________________________

3 0

3 years ago

What is the answer to the equation 4a+26-9a-17=26?

podryga [215]

First you have to put all of your common numbers together. 4a and 9a go together. You then subtract those because 9 is negative (-9). Then you get -5a. Now move on to your other numbers. You have 26 and 17. 17 is negative as well (-17), so you subtract it from 26. That gives you 9.
Your new equation is -5a + 9 = 26
Now you subtract 9 from both sides. Your positive (+9) will cancel out with your negative (-9). Then subtract it from 26. 9 minus 26 is 17.
Now your equation is -5a = 17
Since it's negative, you're going to add it (5) to both sides.
Your 5's cancel out, and 17 + 5 is 22.
a = 22
22 is the answer

5 0

3 years ago