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3 years ago

Please help me with this! If you’re smart you can solve it!

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

5 0

Let L, H, W be the length, height, and width.

Using the 3 clues they gave us, we have:

L x W = 12

L x H = 8

W x H = 6

Our goal is to figure out volume: L x W x H

One way of solving this is to just randomly plug in numbers which should be easy to do for this problem.

Another way is to use substitution.

From first equation: L = 12/W

Plug that into second equation:

12/W x H = 8,

H = (8/12)W = (2/3)W

Plug that into the third equation:

W x (2/3)W = 6,

W x W = 9

W must be equal to 3.

And since we know that L x H = 8

Then L x H x W = (8) x 3 = 24 cm^3

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3 years ago

If f(x)=2x^3-6x^2-16x-20f(x)=2x *3 −6x *2−16x−20 and f(5)=0, then find all of the zeros of f(x)f(x) algebraically.

mihalych1998 [28]

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<h3>How to obtain the solutions to the equation?</h3>

The equation is defined by the rule presented as follows:

f(x) = 2x³ - 6x² - 16x - 20.

One solution for the equation is given as follows:

x = 5.

Because f(5) = 0.

Then (x - 5) is a linear factor of the function f(x), which can be written as follows:

2x³ - 6x² - 16x - 20 = (ax² + bx + c)(x - 5).

This is because the product of a linear function and a quadratic function results in a cubic function.

Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

2x³ - 6x² - 16x - 20 = = ax³ + (b - 5a)x² + (c - 5b)x - 5c.

Then these coefficients are obtained comparing the left and the right side of the equality as follows:

a = 2.

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Hence the equation is:

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Using a quadratic equation calculator, the remaining zeros are given as follows:

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More can be learned about the solutions of an equation at brainly.com/question/25896797

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3 years ago

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2 years ago

Read 2 more answers