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3 years ago

2+2= I NEED HELP 40 points if you answer

Mathematics

2 answers:

andrew11 [14]3 years ago

8 0

Answer:

4 IS THE ANSWER

BRAINLEST??

kati45 [8]3 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

Write an expression that is equivalent to -0.5(20f – 16).

pashok25 [27]

Answer:

- 10f + 8

Step-by-step explanation:

Given expression:

- 0.5(20f - 16)

Distribute and simplify:

-0.5(20f) - 0.5(- 16) =
- 10f + 8

6 0

2 years ago

Read 2 more answers

Mary Grace has 3 more Jolly Ranchers than Isabella. If Isabella has 10 Jolly Ranchers, how many do they have total?

PilotLPTM [1.2K]

Answer:23

Step-by-step explanation:

10+3=13 so that means that mary has 13 and isabella has 10

Then if you add 13+10=23

so they have 23 jolly ranchers in all.

5 0

2 years ago

Read 2 more answers

max bought 2 3/4 punds of green apples, 1 5/8 pounds of yellow apples, and 1 5/8 pounds red apples. the total cost was $5.40. wh

dangina [55]

2 3/4 + 1 5/8 + 1 5/8 =
2 + 1 + 1 = 4 (add the whole numbers)
3/4 + 5/8 + 5/8 = 6/8 + 5/8 + 5/8 = 16/8 = 2 (add the fractions)
4 + 2 = 6 total lbs

5.40 for 6 lbs = 5.40/6 = 0.90 (so the apples cost 90 cents per lb)

7 0

2 years ago

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$