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3 years ago

Express 47% as a decimal...

Mathematics

2 answers:

liubo4ka [24]3 years ago

7 0

47% can be turn to a decimal by dividing it by 100 which will give you 0.47

belka [17]3 years ago

7 0

To get the decimal of 47%, multiply it by 100 and then you will get your decimal of .47

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The range of the function defined as y = 5x is

snow_tiger [21]

The answer, i believe, is B

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2 years ago

Isabella has a board that is 5.24 feet long and 1.34 feet wide.

Masteriza [31]

Answer:

Length of 1 piece= Length of total divided by 8

Step-by-step explanation:

Length of total= 5.24 feet long

Width of total= 1.34 feet wide

Width is divided by 1 line so, there are 2 parts.

Width= 1.34 divided by 2

Width= 0.67 feet wide

Length is divided by 7 lines, so there are 8 parts.

Length= 5.24 divided by 8

Length=0.655 feet long

They are asking for formula to find the length of each piece

Length of 1 piece= Length of total divided by 8

Hope that helps!

8 0

3 years ago

In the diagram below, O is circumscribed about quadrilateral DEFG. What is

Nimfa-mama [501]

Since O is circumscribed about quadrilateral DEFG, the value of x is equal to: D. 68°.

<h3>What is a supplementary angle?</h3>

A supplementary angle can be defined as two (2) angles or arc whose sum is always equal to 180 degrees. Mathematically, a supplementary angle can be calculated as follows:

Q + R = 180°.

In Geometry, the opposite angles of any cyclic quadrilateral that is inscribed inside a circle always form a supplementary angle. Thus, we would determine the value of x by using the mathematical expression above:

x + 112° = 180°

x = 180° - 112°

x = 68°

Read more on supplementary angle here: brainly.com/question/12542846

#SPJ1

8 0

2 years ago

Determine whether the given vectors are orthogonal, parallel or neither. (a) u=[-3,9,6], v=[4,-12,-8,], (b) u=[1,-1,2] v=[2,-1,1

nevsk [136]

Answer:

a) $u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

$|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}$

$|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}$

$cos \theta = \frac{uv}{|u| |v|}$

$\theta = cos^{-1} (\frac{uv}{|u| |v|})$

If we replace we got:

$\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi$

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

b) $u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5$

$|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}$

$|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}$

$cos \theta = \frac{uv}{|u| |v|}$

$\theta = cos^{-1} (\frac{uv}{|u| |v|})$

$\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557$

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

c) $u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0$

Since the dot product is equal to zero then the two vectors are orthogonal.

Step-by-step explanation:

For each case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

Part a

u=[-3,9,6], v=[4,-12,-8,]

The dot product on this case is:

$u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}$

$|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{uv}{|u| |v|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{uv}{|u| |v|})$

If we replace we got:

$\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi$

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

Part b

u=[1,-1,2] v=[2,-1,1]

The dot product on this case is:

$u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}$

$|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{uv}{|u| |v|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{uv}{|u| |v|})$

If we replace we got:

$\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557$

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

Part c

u=[a,b,c] v=[-b,a,0]

The dot product on this case is:

$u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0$

Since the dot product is equal to zero then the two vectors are orthogonal.

5 0

3 years ago

Read 2 more answers

What is 1875 ÷ 125 (show ur work long divison)

Colt1911 [192]

Answer:

15 R7

Step-by-step explanation:

015

32/ 487

0

32

167

160

remainder 7

7 0

2 years ago