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adell [148]
3 years ago
15

Please help I can't work out the gradient​

Mathematics
1 answer:
Annette [7]3 years ago
8 0

Answer:

a is 2.5

b is 1

gradient is rise over run

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I need need help on this
Crazy boy [7]

Answer:

points A, B and D are all in the same plane but not all are on the same line

Step-by-step explanation:

points A, C, D are all collinear which means they must also be coplanar

3 0
3 years ago
In the literal equation below, what do C and F represent?
Zolol [24]
Answer: Variables

F and C are placeholders for numbers. They are called variables because they are allowed to vary, or change. If you change C then it affects F, and vice versa. If the values for the placeholders is not allowed to change, yet it holds a number, then it is considered a constant. In this case, we don't have constants or else the formula isn't too useful. 
3 0
3 years ago
If f(x) = -7x + 5x2 + 10, what does f(-2) equal?
aksik [14]

Answer:

f(-2) = 44

Step-by-step explanation:

Hello there! Lets get started solving this function!

For a function, whenever we see f(x) = ... , the function is simply asking the value of the equation at x! So, if replace f(x) with f(-2), we simply substitute x with -2 in the equation! Lets get started!

f(x) = -7x + 5x^{2} + 10\\f(-2) = -7(-2) + 5(-2)^{2} + 10\\f(-2) = 14 + 20 + 10\\f(-2) = 44\\

First, we can write the original function. Next, we substitute in -2 for x. Then, we find our final terms. Finally, we are given that f(-2) = 44.

Hope this helps! Remember, math is fun!

7 0
3 years ago
Select the decimal that is equivalent to 1/8
iogann1982 [59]
The answer is 0.125....................................
5 0
3 years ago
Read 2 more answers
Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50
steposvetlana [31]

<u>Answer-</u>

f(2)= 6x^4-10x^3+40x-50=46

<u>Solution-</u>

The given function is,

\Rightarrow f(x)= 6x^4-10x^3+40x-50

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= 96-80+80-50

\Rightarrow f(2)= 96-50

\Rightarrow f(2)= 46

Therefore, f(2) was found to be 46.


7 0
3 years ago
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