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solong [7]
4 years ago
11

Heeeeeeeeeeeeelpppppppppppppppp!

Mathematics
1 answer:
Alexus [3.1K]4 years ago
5 0
To figure out which of the coordinates don't work, we need to substitute their values of x and y to figure out if they work or not. We will know they don't work if the result we get is something crazy like 2=25. 

Substitute the values of x and y from a
\left \{ {{5 (6) = 3(5) +15 } \atop {6(5)=10(6)-30}} \right.

Now we simplify
\left \{ {{30 = 30 } \atop {30=30} \right. 
Since this is true we know that the point (5,6) works. Now let's move onto B. 

Once again, we substitute. 
\left \{ {{5 (12) = 3(-15) +15 } \atop {6(-15)=10(12)-30}} \right.

This simplifies to 
\left \{ {{60=-30} \atop {-90=90} \right.
Since this is obviously not right, we know that is the point that doesn't work in this system of equations. 
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yan [13]

Answer:

the answer is 76

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4 years ago
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Find the common factor of all the terms of the polynomial 15x-12x
IrinaVladis [17]

Answer:

Step-by-step explanation:

x is common to both 15x and -12x; so is 3.  Thus, the common factor is 3x.

7 0
4 years ago
-Russell wants to buy three identical gift cards. hehe wants to make sure his total cost is no more than $2 above or below $60.
erastova [34]

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|60+3c|<2

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Step-by-step explanation:

4 0
3 years ago
I need to change the subject to x
ira [324]

Answer:

h) (x+4t²)/4= 3V

x+4t²= 4*3V

x+4t²=12V

x=12V-4t²

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7 0
3 years ago
Plz help ill give u brainlist
g100num [7]
Step One
Find the base area  of the large hexagon as though the smaller one was not removed.

Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.

Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)

Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.

Area of the remaining piece = area of large hexagon - area of the small hexagon

Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)

Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18

I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3

3 0
3 years ago
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