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3 years ago

I HAVE 1 MATH QUESTION THAT I REALLY REALLY NEED HELP ON! ONLY COMMENT IF YOU ARE GOING TO HELP. PLEASE I NEED HELP ASAP

Mathematics

1 answer:

babymother [125]3 years ago

6 0

Use y2-y1/x2-x1
So 0-5/3-2
-5/1= m= -5
Then plug it into y=MX+B

0= -5(3)+b
0= -15+b
b=15
y=-5x+15

So I hope this helps but I'm not sure how to plug it into that's equation. The rest of my work is rigt

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Can someone help me and explain how you did it?

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slope: -3/5

y-intercept: (0, 4)

slope-intercept form: y = -3/5x + 4

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<h3><u>Finding the slope</u></h3>

To find the slope of this line, you would take two points from the table and substitute their coordinates into the slope formula.

Slope formula: $\frac{y_2-y_1}{x_2-x_1}$

I'm going to use the points (0, 4) and (5, 1). You can really use any point from the table. Substitute these points into the formula to find the slope.

(0, 4), (5, 1) → $\frac{1-4}{5-0} \rightarrow \frac{-3}{5}$

This means the slope of the line is -3/5.

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The y-intercept will always have the value of x be 0 (so the point is solely on the y-axis), so by looking at the table we can see that the y-intercept is at (0, 4).

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point-slope form: y - y1 = m(x - x1) --you'll be substituting the point coordinates and slope into y1, x1, and m.

y - (4) = -3/5(x - (0))

Simplify.

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