Answer:
frequency of allele “A” is .39
frequency of allele “a” is .77
Explanation:
hardy weinberg equation
p^2 + 2pq + q^2 = 1 or (A+a)^2
p^2 = (AA)
2pq = (Aa)
q^2 = (aa)
AA -> 15/100 = .15
Aa -> 25/100 = .25
aa -> 60/100 = .60
if p^2 = AA = .15 then A = √.15 = 0.38729833462 = .39
if q^2 = aa = .60 then a = √.60 = 0.77459666924 = .77
wikipedia quoraAnkitGauba
If the results show that 21% of the nucleotides contain adenine, then the cytosine fraction in vivo is 29% and the thymine fraction is also 21% (options A and C).
<h3>Define double helix model of DNA?</h3>
- DNA is a double helix molecule made up of two long strands of nucleotides.
- There are four types of nucleotides in DNA, each containing a different nitrogenous base: adenine, guanine, thymine, cytosine.
- Adenine always pairs with thymine and guanine pairs with cytosine, according to the base-pairing rules.
- As a result, the percentage of adenine equals the percentage of thymine, and the remaining percentage equals guanine + cytosine (29 + 29 = 58 >> 58 + 21 + 21 = 100).
- Therefore, if the results show that 21% of the nucleotides contain adenine, then the percentage of cytosine in vivo is 29% and the percentage of thymine is also 21%
To know more about double helix model of DNA, visit:
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The complete question is as follows:
The DNA content for an organism is analyzed. The results showed that 21% of the nucleotides contained the nitrogenous base adenine. What else can be inferred based on this data? Select all that apply
A) The percentage of cytosine is 29%.
B) The percentage of adenine is 21% for all organisms.
C) The percentage of thymine in the organism is also 21%.
D) The percentage of guanine in the organism is also 21%.
E) The percentage for cytosine in the organism is also 21%.
<span>The offspring would have twice the number of chromosomes it's supposed to have.</span>
