A
A square matrix is invertible if its determinant is not zero.
The determinant for this matrix is

so it does not have an inverse because its determinant is zero.
Answer:
=5
Step-by-step explanation:
4-9= -5
2-3 = -1
=5
.....
Answer:
the co_ordinate of d is 0
The given expression is 2x-3 .
So when x =1, we will get 2(1)-3 = 2-3 =-1
When x=2, we will get, 2(2) -3 = 4-3 =1
When x=3, we will get 2(3)-3 = 6-3=3
When x=4, we will get 2(4)-3 = 8-3=5
So the required result of the expansion is -1+1+3+5=8
Correct option is the second option .
Choice A is the answer which is the point (1,-1)
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How I got this answer:
Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.
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checking choice A
plug in (x,y) = (1,-1)



This is true because -3 is equal to itself. So this is the answer.
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checking choice B
plug in (x,y) = (2,4)



This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.
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checking choice C
plug in (x,y) = (-2,3)



This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.
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checking choice D
plug in (x,y) = (3,4)



This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.