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inysia [295]
2 years ago
13

I think of a number. If I divide the sum of 6 and the number by 3,the result is 4 more than one quarter of the number. Find the

number.
Mathematics
1 answer:
Alex17521 [72]2 years ago
7 0

Answer:

24

Step-by-step explanation:

Let the number be x.

Sum of the number and 6: 6+x

Divide it by 3: \frac{6+x}{3}

Result is 4 more than one quarter of the number:

\frac{6+x}{3} =4+\frac{1}{4} x

Multiply both sides by 12:

\frac{6+x}{3}\cdot \:12=4\cdot \:12+\frac{1}{4}x\cdot \:12

Simplify:

4\left(x+6\right)=48+3x

Expand:

4x+24=48+3x

Subtract 24 from both sides:

4x+24-24=48+3x-24

4x=3x+24

Subtract 3x from both sides:

4x-3x=3x+24-3x

x=24

The number is 24.

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If a=12 and 120% of a is equal to 80% of b then what is a+b
mojhsa [17]
A=12
120% of a =80% of b
120%a = 80%b
120a/100 = 80b/100
Divide through by 100
120a = 80b
Divide through by 80
120a/80 = b
But a=12
120x 12/80 = b
18 = b
b = 18

a+b = 12 + 18 = 30
8 0
2 years ago
Two kinds of tickets to an outdoor concert were sold: lawn tickets and seat tickets. Less than 400 tickets in total were sold. L
miskamm [114]

Answer:

Tickets to sit on the bench (b) = 150

Tickets to sit on the lawn (l) = 200

Step-by-step explanation:

Tickets to sit on a bench (b)cost $75 each.

Tickets to sit on the lawn (l) cost $40 each

350 tickets had been sold

$19,250 had been raised through tickets sales

This forms a simultaneous equation:

b + l = 350 ... (i)

75b + 40l = 19,250 ... (ii)

Multiplying (i) by 40 and (ii) by 1 we get;

40b + 40l = 14,000 ... (i)

75b + 40l = 19,250 ... (ii)

Subtracting (ii) - (i) we get;

35b = 5250

b = 5250 ÷ 35 = 150

7 0
3 years ago
Solve for S<br><br> P=4s<br><br> Please answer!!!!
Karolina [17]

Answer:

b

Step-by-step explanation:

divide both sides of the equation by 4 to leave s by itself

6 0
3 years ago
Read 2 more answers
What is the answer in simplest form?
Arte-miy333 [17]

Answer:

P(Selecting a student aged 12)= (13/27)

Step-by-step explanation:

first find the value of (e), by getting the value of (b). check no.2.

8 0
2 years ago
Find all solutions of the equation in the interval [0, 2pi).
mina [271]

Answer:

x = 0 , π

Step-by-step explanation:

-4 \sin x = 1 - cos^2 x

  • Rewrite it by using the identity \sin^2x + \cos^2x = 1

=> -4\sin x = \sin^2x

  • Add 4sin x to both the sides.

=> -4\sin x + 4\sin x = sin^2x + 4\sin x

=> \sin^2x + 4\sin x = 0

  • Take sin x common from the expression in L.H.S.

=> \sin x(\sin x + 4)=0

Here , we can get two more equations to find x.

1) \sin x(\sin x + 4)=0

  • Divide both the sides by sin x

=> \frac{\sin x(\sin x + 4)}{\sin x} = \frac{0}{\sin x}

=> \sin x + 4 = 0

  • Substract 4 from both the sides.

=> \sin x + 4 - 4 = 0 - 4

=> \sin x = -4

=> x = No \; Solution

2) \sin x(\sin x + 4)=0

  • Divide both the sides by (sin x + 4)

=> \frac{\sin x(\sin x + 4)}{\sin x + 4} = \frac{0}{\sin x + 4}

=> \sin x =  0

=> x = 0 \; , \pi over interval [0 , 2π).

5 0
3 years ago
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