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2 years ago

Angela plays soccer and golf for a total of 125 minutes every day. She plays soccer 45 minutes more than she plays golf.

Mathematics

1 answer:

evablogger [386]2 years ago

8 0

Answer:

https://share.nowblox.com/racedose39

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Twice a number, increased by the sum of the same number and five.

melisa1 [442]

Answer:

2x+(x+5)

not 100% sure but this is what i got

Step-by-step explanation:

8 0

2 years ago

Find the indicated side length.

Schach [20]

Answer: KL = 5.3

Step-by-step explanation:

Set up the proportion, cross multiply, and solve for the missing side:

$\frac{JL}{GL} = \frac{KL}{HL}$

$\frac{4}{10} = \frac{KL}{8 + KL}$

4(8 + KL) = 10(KL)

32 + 4KL = 10KL

32 = 6KL

$\frac{32}{6}=KL$

KL = 16/3 = 5.3

8 0

3 years ago

What is the solution to the equation x/2-4=6

-Dominant- [34]

Answer

x = 20

Explanation

Multiply the entire equation by 2 to get rid of the fraction.

x/2 * 2 = x

-4 * 2 = -8

6 * 2 = 12

Now, we have:

x - 8 = 12

To complete, add 8 to both sides

x = 20

3 0

2 years ago

Read 2 more answers

HELP PLEASE THANKS (;

Zielflug [23.3K]

You have 2 equations that are both equal to y. If they are both equal to y, then by the transitive property of equality, they are equal to each other (if a = b, and b = c, then a = c).
5x - 17 = x + 3 and
4x = 20 and x = 5. Now sub in that x value of 5 to solve for y:
y = 5 + 3 and y = 8. So the ordered pair is (5, 8)

5 0

2 years ago

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an

Harrizon [31]

Answer:

$x^{1}$ wives

$x^{2}$ sacks

$x^{3}$ cats

$x^{4}$ kits

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

$x^{1}$ wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

$x^{2}$ sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

$x^{3}$ cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

$x^{4}$ kits

8 0

2 years ago