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AfilCa [17]
3 years ago
7

A compound is formed when a sulfur atom and six fluorine atoms share electrons. What is the name of the compound?

Biology
2 answers:
Crank3 years ago
6 0

Answer;

Sulfur hexafluoride

Explanation;

-Sulfur hexafluoride (SF6) is an inorganic, colorless, odorless, and non-flammable greenhouse gas.

-Sulfur hexafluoride has an octahedral geometry, consisting of six fluorine atoms attached to a central sulfur atom. It is a hypervalent molecule.

-Being a nonpolar gas, it is poorly soluble in water but soluble in nonpolar organic solvents. It is generally transported as a liquefied compressed gas.

-It is used in the electrical industry as a gaseous dielectric medium for high-voltage circuit breakers, switchgear, and other electrical equipment, often replacing oil filled circuit breakers (OCBs) that can contain harmful PCBs.

Pani-rosa [81]3 years ago
5 0
<span>The name of the compound is Sulfur hexafluoride</span>
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Why

Explanation:

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_____ exhibit two radial body forms, the polyp and the medusa, and use stinging cells to capture prey.
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4 years ago
A woman with normal vision has a son. The woman’s maternal grandfather is color-blind. What is the probability that the son is c
Reptile [31]

Answer:

= \frac{1}{4}

Explanation:

Given that the woman’s maternal grandfather is color-blind, then it is possible that the woman is a carrier of color-blind allele.

Then probability that the woman is a carrier of color-blind allele is = \frac{1}{2}  

So if a carrier woman cross with a normal man

Let say the gene of the carrier woman is: XX^c

and the normal man = XY

so if we have a cross between  XY and XX^c; we have:

                     X                     Y

X                   XX                 XY

X^c                 XX^c                 X^cY

we can see the offspring to be :

XX =normal unaffected female

XY = normal unaffected male

XX^c = carrier female for color-blind

X^cY = carrier male for color-bind

Then probability that of  inheriting defective allele = \frac{2}{4} = \frac{1}{2}

Let's not forget that the probability that the woman is a carrier of color-blind allele is = \frac{1}{2}  

∴  the probability that the son is colorblind = \frac{1}{2}*\frac{1}{2}

= \frac{1}{4}

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Answer:

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