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3 years ago

9x+y=28 3x+3y=(-12) Solve using elimination

Mathematics

1 answer:

Rzqust [24]3 years ago

5 0

Answer:

(x, y)=(4,-8)

Step-by-step explanation:

9x+y=28

3x+3y=-12 /:(-3)

9x+y=28.......(1)

-x-y=4......(2)

9x+y=28

(1)+(2): 8x=32

9x+y=28

x=32/8

9x+y=28

x=4

9*4+y=28

x=4

36+y=28

x=4

y=28-36

x=4

y=-8

x=4

(x, y) =(4,-8)

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Serjik [45]

Answer:

one solution

Step-by-step explanation:

2/3(3y+6)=0

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3 years ago

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3 years ago

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Step-by-step explanation:

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2 years ago

Ms. Gadget car broke down on the turnpike. Acme town Ig charged $30 plus $3 per mile to tow the car. If ms. Gadget paid $162, ho

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2 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago