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Nadusha1986 [10]
2 years ago
6

9x+y=28 3x+3y=(-12) Solve using elimination

Mathematics
1 answer:
Rzqust [24]2 years ago
5 0

Answer:

(x, y)=(4,-8)

Step-by-step explanation:

9x+y=28

3x+3y=-12 /:(-3)

9x+y=28.......(1)

-x-y=4......(2)

9x+y=28

(1)+(2): 8x=32

9x+y=28

x=32/8

9x+y=28

x=4

9*4+y=28

x=4

36+y=28

x=4

y=28-36

x=4

y=-8

x=4

(x, y) =(4,-8)

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A ruler is 12 inches long. What is the of this ruler
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labwork [276]

Answer:

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Step-by-step explanation:

<u>Substitution</u>

Substitute for y:

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<u>Elimination</u>

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If you think for a bit about what the graph looks like, you realize both lines cross at their y-intercept, (0, -2248). That point of intersection is the solution to the system of equations.

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Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap
bazaltina [42]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)

A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)

C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

AC=\sqrt{12^2+12^2}

AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

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