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3 years ago

Find the slope of the line: (-2,0);(11,0)

Mathematics

2 answers:

mafiozo [28]3 years ago

7 0

Answer:

the slope is 0 your welcome

Pavel [41]3 years ago

5 0

Your y value is staying at zero, meaning it is not increasing. this means your line is horizontal so it has a slope of 0. hope that makes sense!

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2(y+1) for y =2 (will pick brainliest if right) A:6 B:5 C:7 D:8

Katen [24]

Answer:

A. 6

Step-by-step explanation:

pretty sure its right

5 0

3 years ago

Read 2 more answers

Looking for the answer to this

SashulF [63]

<h2>Required Answer :-</h2>

Given system of linear equations are ,

x + y = 2
-3x + y = 2

And we need to find the Solution of the linear equation . So let's Firstly number the equations .

$\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}$

→ Multiplying equⁿ (i) by 3 ,

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

→ Adding the two equations ,

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

=> y = 2

→ Put y = 2 in (i) ,

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

<h3>★ Hence the required solution is ( 0 , 2 ) .</h3>

7 0

3 years ago

Flying against the wind, a jet travels 4400mi in 8 hours. Flying with the wind, the same jet travels 5820mi in 6 hours. What is

Anna [14]

distance=6390km; time=9 hrs; rate=710kph
With the wind Data:
distance=5150km; time=5hrs; rate=1030kph
EQUATIONS:

airspeed+jetstream=1030
airspeed-jetstream=710
Subtract these equations to get:
2jetstream=320kph
jetstream=160mph

5 0

3 years ago

Draw a number line please

Mkey [24]

Answer:

1 2 3 4 5 6 7 8 9 10.... etc

Step-by-step explanation:

What number goes between the numbers that I put.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%283x%20%2B%204%29%20%20-%207%20log_%7B4%7D%7Bx%7D%5E%7B2%7D%20%20%2B%20%20log_%

olga2289 [7]

First of all, we need all logarithms to have the same base. So, we use the formula

$\log_a(b)=\dfrac{\log_c(b)}{\log_c(a)}$

To change the second term as follows:

$\log_4(x^2)=\dfrac{\log_2(x^2)}{\log_2(4)}=\dfrac{\log_2(x^2)}{2}$

Finally, using the property

$\log(a^b)=b\log(a)$

we have

$\dfrac{\log_2(x^2)}{2}=\log_2(x)$

So, the equation becomes

$\log_2(3x+4)-7\log_2(x)+\log_2(x)=2 \iff \log_2(3x+4)-6\log_2(x)=2$

We can now use the formula

$\log(a)-\log(b)=\log\left(\dfrac{a}{b}\right)$

to write the equation as

$\log_2(3x+4)-6\log_2(x)=2 \iff \log_2(3x+4)-\log_2(x^6)=2 \iff \log_2\left(\dfrac{3x+4}{x^6}\right)=2$

Now consider both sides as exponents of 2:

$\dfrac{3x+4}{x^6}=4 \iff 4x^6-3x-4=0$

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be

5 0

4 years ago