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nika2105 [10]
3 years ago
6

What is the least common multiple of 4x^3, 9y, and 12x^3y

Mathematics
2 answers:
NARA [144]3 years ago
8 0

The LCM for 4x^3, 9y, 12x^3y, is the numeric part 36 multiplied by the variable part 36x^3y.

blondinia [14]3 years ago
5 0

Answer: 36x^3y

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

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A rectangle is plotted on a coordinate plane. The four vertices are located at (−5,5), (−5,−3), (2,5), and (2,−3). What is the a
n200080 [17]

Answer:

56 square units

Step-by-step explanation:

I'd recomend using something like "Desmos" to plot the points so then you can see the points and the rectangle. Then count the length and width. For the this rectangle the length was 8 and the width was 7, multiply these and you get the answer of 56 sqaure units.

8 0
3 years ago
The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

5 0
3 years ago
Help, I don’t understand this DeltaMath question
djyliett [7]
I can use the angle and the length of JH to find the length of IJ.

To do this, I look at the relationship IJ and JH have to the 52 degree angle. JH is opposite to angle I, and IJ is adjacent to angle I. Because the two side lengths are opposite and adjacent, I use the tangent function to solve this.

Tangent of an angle = the length of the opposite side / the length of the adjacent side. This is just another way to say tan(x)=opposite/adjacent

Now I can fill in what I know...
tan(52)=4.2/x
Now, I want to isolate x.
tan(52) = 4.2/x
x(tan(52))=4.2
x=4.2/tan(52)

Now I put 4.2/tan(52) into a calculator and get x = 3.3 ft

Hope this helps!
7 0
3 years ago
Find the Area of the figure below,
murzikaleks [220]

Answer:

169.1 unit^2 to the nearest tenth.

Step-by-step explanation:

Area of the parallelogram = base * height

= 24 * 6 unit^2.

Area of the semicircle = 1/2 pi r^2.

Here r = 1/2 * 8 = 4.

So the area is 1/2 * pi * 4^2

= 8pi unit^2.

The area of the whole figure = 24*6 + 8pi

= 169.13 unit^2.

3 0
3 years ago
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed.
LenaWriter [7]

Answer:

28 meters cubed.

Step-by-step explanation:

Since we know that the volume of a sphere is 4/3 the volume of a cylinder, we can multiply 21*4/3. 21*4 will equal 84 and 84/3 would be 28. So the volume of the sphere would be 28 meters cubed.

5 0
3 years ago
Read 2 more answers
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