The domain is t=0 to t=3.2 and range is y = 0 to 57.125 feet.
<u>What are Domain and range of a Function?</u>
- The range of values that we are permitted to enter into our function is known as the domain of a function.
- The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input.
- After we enter an x value, the function outputs this sequence of values. The y values are those.
- A function can be compared to a piece of equipment on an assembly line.
- A few screws and nuts are located on one end of the assembly line, while a car is located on the other. The function is the device in the center. The domain is the screws and bolts that we insert into the machine. The car at the other can be thought of as the range.
Given function is : y = -16t^2 + 50t + 4
It hits the ground when y=0
0 = -16t^2 + 50t + 4
8t^2 -25t -2 = 0
t = 25/16 + (1/16)sqrt(625+64) = (25+26.25)/16 = 51.25/16 = 3.2 seconds
domain is t=0 to t=3.2 [3.2]
take the derivative and set it equal to zero to find maximum height
-32t +50 = 0
t = 50/32 = 25/16 = 1.5625 seconds
-16(25/16) + 50(25/16) + 4 = 34(25/16) + 64/16 = (17(25)+32)/8 = 57.125 = maximum height
range is y = 0 to 57.125 feet. the discus goes from 4 feet to 57 1/8 feet and back down to 0 feet.
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11 because -7 subtracted by 4 add kore to the 7 so think of it this way -7 is a bad guy and 4 is a bad guy to because its a subtraction so if both bad guys combine you get 11 because a negative with negative makes a positive so its 11
54554/99999. I think I am right but sorry if I am wrong.
Answer:
Formula for area of a circle;
<u>A = πr^2</u>
where pi is 3.14 in this case, and r is the radius squared
Plug in the actual values;
A = 3.14 x 11^2
A = 3.14 x 121
A = 379.94 square feet
