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Arada [10]
3 years ago
7

2 12 divided by 14 . (a) Write a real-world problem for the division.

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

0.0119047619 is the answer

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Two fifths of a number equals 564. what is the number
masya89 [10]

Answer:

1410

Step by step explanation:

<em>2</em><em>/</em><em>5</em><em>x</em><em>=</em><em>5</em><em>6</em><em>4</em>

<em>5</em><em>/</em><em>2</em><em>*</em><em>2</em><em>/</em><em>5</em><em>x</em><em>=</em><em>5</em><em>6</em><em>4</em><em>*</em><em>5</em><em>/</em><em>2</em>

<em>x</em><em>=</em><em>1</em><em>4</em><em>1</em><em>0</em>

<em>Proof</em><em>:</em><em> </em><em>2</em><em>/</em><em>5</em><em>*</em><em>1</em><em>4</em><em>1</em><em>0</em><em>=</em><em>5</em><em>6</em><em>4</em>

Hope it helps <3

5 0
3 years ago
Read 2 more answers
A fair spinner has 10 equal sections: 3 red, 3 blue and 4 green.
Natalka [10]

Answer:

10

Step-by-step explanation:

cool ok byeeeeeeeeeee

6 0
3 years ago
Which of the following illustrates the truth value of the given statements? January is the first month of the year or December i
Dafna11 [192]
First, the need to determine if the statements are true or false.

1) January is the first month of the year. (This statement is true)
2) December is the last month of the year. (This statement is also true)

With this in mind we can determine that what will illustrate the truth value would be:

T T -> T

In other words, since the first statement is true and the second statement is also true then conjunction of both statements would be true.
5 0
3 years ago
Read 2 more answers
Please help me thank you very much
frez [133]
Answer is A
Triangle UVW ~ Triangle UWT ~ Triangle  WVT
5 0
3 years ago
(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-
Tanya [424]

Step-by-step explanation:

(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-20=0

2x²+6x-20

2(x²+3x-10)

the factors are 2 and (x²+3x-10)

(2) Factor the polynomial completely. (4 points: 2 point for each factor)

2(x²+3x-10)

2(x²-2x+5x-10)

2(x(x-2) + 5(x-2))   group like terms

2(x+5)(x-2)

(3) If a product is equal to zero, we know at least one of the factors must be zero. And the constant factor cannot be zero. So set each binomial factor equal to 0 and solve for x, the width of your project. (2 points: 1 point for each factor)

constant = 2  cannot be zero

the other factors are (x+5) and (x-2)

(x+5)=0 => x= -5

or

(x-2)=0 => x=2

(4) What are the dimensions of your project? Remember that the width of your project is represented by x. (2 points: 1 point for each dimension)

thank you so much, sorry if it's a little confusing!!  

(it is indeed confusing, because physical dimensions cannot be negative)

The dimensions of the project (assumed a rectangle) are +2 and -5

3 0
3 years ago
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