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elixir [45]
3 years ago
7

Alex wrote 103.903 in expanded form as 100+3x1+9x1/100+3x1/1000. Explain his mistake. Then tell how to correct it.

Mathematics
1 answer:
masya89 [10]3 years ago
7 0
Here is the mistake is on 9x1/100 because after decimal 9 is there means
9 has to be multiplied by 1/10 to get the 0.9

Here if we expand the 103.903 then from left to right
1 = 1x100 +
0 = 0x10   +
3 = 3x1     +
9 = 9x1/10+
0 = 0x1/100+
3 = 3x1/1000 = 103.903
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Step-by-step explanation:

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Sphinxa [80]

Answer:

3.6666 (I didn't round)

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Step-by-step explanation:

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A repeating decimal is one that keeps going and repeats a pattern. This is decimal keeps going and repeats a pattern so it is a repeating decimal.

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4 0
3 years ago
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AURORKA [14]

According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

<h3>What is the behavior of a functions close to one its vertical asymptotes?</h3>

Herein we know that the <em>rational</em> function is q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15), there are <em>vertical</em> asymptotes for values of x such that the denominator becomes zero. First, we factor both numerator and denominator of the equation to see <em>evitable</em> and <em>non-evitable</em> discontinuities:

q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15)

q(x) = [(x - 3)²] / [(x - 3) · (x - 5)]

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There are one <em>evitable</em> discontinuity and one <em>non-evitable</em> discontinuity. According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

To learn more on rational functions: brainly.com/question/27914791

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