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Likurg_2 [28]
3 years ago
15

Describe the vector as an ordered pair around coordinates to the nearest 10th the diagram is not drawn to scale

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

x = r cosΘ

y = r sinΘ

with r = 54 and Θ = 69°, thus

x = 54cos69° ≈ 19.4

y = 54sin69° ≈ 50.4

Thus (54, 69° ) as an ordered pair

= \left[\begin{array}{ccc}19.4\\50.4\\\end{array}\right]

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How big is the board
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3 years ago
Are the two triangles below similar?
Luda [366]

Answer :- Yes the two triangles are similar because there are two pairs of congruent corresponding angles.

Explanation:-

In Δ ABC

∠A=30° , ∠C=65 °

By angle sum property of triangle

∠A + ∠B + ∠C= 180°

⇒∠B= 180°-∠A-∠C=180°-30°-65°=85°

⇒∠B=85°

Now in ΔABC and ΔDEF

∠A=∠D=30° and ∠B=∠E=85°

⇒ there are two pairs of congruent corresponding angles.

So by AA-similarity criteria

ΔABC ≈ ΔDEF




3 0
3 years ago
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Can someone please tell me what is the solution
vovangra [49]

Answer:

\frac{1}{4} \tan {}^{4}(x) + c

8 0
3 years ago
The volume of a cube depends on the length of its sides. This can be written in function notation as v(s). What is the best inte
faust18 [17]
The volume of a cube formula is v(s)=s^3. If you plug in 3 for s, you will find that v(s) would in fact equal 27. Thus the length of the sides are 3 and the volume is 27.
5 0
3 years ago
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Help QUICKKKKK please
Svetllana [295]

Answer:

Step-by-step explanation:

Remark

The exposed perimeter of the triangle is just the two smaller legs of the right triangle (6 + 8) + 10 units at the bottom of the rectangle + two 1/2 circles.

The area of the figure is the area of the triangle at the top + the area of the two 1/2 circles + the rectangle in the middle.

Givens

  • Shortest Triangle Leg = 6
  • Middle Triangle Leg = 8
  • Diameter of the 2 half circles
  • pi  = 3.14
  • width of the rectangle in the middle = 8
  • Length of the rectangle = 10
  • d = 8
  • r = d/2 = 8/2 = 4

Formula

A

Perimeter = 2 legs of the triangle + 2 half circles + bottom line

B

Area = (1/2) Leg1*leg2 + pi * r^2 + L * w

Solution

A Perimeter

Perimeter = 6 + 8 + 2*pi *r + 10

Perimeter = 24 + 2*3.14*4

Perimeter = 25.12

B Area

Area = 1/2 * 8 * 6 + 3.14*4^2 + 10* 8

Area = 24 + 50.24+ 80

Area = 150.24

Answer

P = 25.12

Area = 150.24

5 0
2 years ago
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