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zaharov [31]
3 years ago
14

How do you remove is the door knob from the surface area of your bedroom door

Mathematics
2 answers:
pogonyaev3 years ago
3 0

Answer:

by adding the circle of area below the doorknob and removing the surface area of the knob itself

Step-by-step explanation:

nataly862011 [7]3 years ago
3 0

Answer:

with a skrew driver

Step-by-step explanation:

remove the skrews with the skrew driver and the you should be able to pull it out

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Solve for y. identify the slope and y-intercept. then graph the equation.<br><br> y=-3x+1
stealth61 [152]

Answer:

the slope -3, slope meaning rate of change and y intercept is 1.

hope that answers your question

(used desmos to graph, good stuff!!!)

4 0
2 years ago
What is the common denominator for 5/8 and 1/4
Troyanec [42]

Answer:

i think the answer is 8 or it could be 2 or 4 :)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta
Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean \mu and standard deviation 0.68 in dollars.


We average n=45 samples to get \bar{x}.


The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write


\sigma = 0.68 / \sqrt{45} = 0.101


Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains \mu.


Our interval takes the form of ( \bar{x} - z \sigma, \bar{x} + z \sigma ) as \bar{x} is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".


Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.


Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.


With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.


We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is


( \bar{x} - 1.65 (.101),  \bar{x} + 1.65 (.101) )


in other words a margin of error of


\pm 1.65(.101) = \pm 0.167 dollars


That's around plus or minus 17 cents.




3 0
3 years ago
Read 2 more answers
Determine the solution to the system of equations below.<br> x-3y=1<br> 3x-5y=11
EastWind [94]
The answer you are looking for is (7, 2).
5 0
3 years ago
Kyle anticipates that he will be in a higher tax bracket when he retires than he's in now.
kupik [55]

Answer:

For Kyle, a Roth IRA would be a better choice if he wants to pay less tax, since the tax will be collected when he contributes funds.

Explanation:

If kyle falls in higher tax bracket when he retires, then Roth IRA is the best option.Roth IRA is an individual's retirement saving account that offers valuable tax benefits, that is the money invested within the Roth IRA is tax free and withdrawal in retirement will be tax free too.That is you contribute money now that you'll pay income taxes on this year, but the withdrawal will be tax free during retirement.

3 0
3 years ago
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