Question

The perimeter of a rectangular playing field is 280 feet. The length of the field is 20 feet more than the width. What are the dimensions of the playing field? (You need to find the length and the width.)

Answer 1

Answer:

L =80

w=60

Step-by-step explanation:

P =280

L =w +20

=>L +w=280 :2 =140

w+20+w=140

2w=140 - 20

2w =120

w=120 :2 =60

L=60 +20 =80

P =2L +2w

P =2 ×80 +2 ×60

P=160 +120

P=280

Answer 2

Answer:

L = 80    ,   w=60

Step-by-step explanation:

l= w+20

perimeter: l+w+l+w=280

Plug in the value of L in place of L

(w+20)+w+(w+20)+w=280

Combine Like terms

and then separate the variables and knowns by subracting 40 from both sides

4w+40=280

     -40   -40

Divide by 4 from both sides so (W) would be alone

4w=240

÷4     ÷4

You solved half the question now

               w = 60

Remember the L at the top

we now know the value of W

so

L=(60)+20

L=80

just to be sure

80+80+60+60=280

you are welcome