500? If you're trying to find x...
This is very similar to the last question:-
0.51No = No e^_0.0001t
t = ln 0.51 / 0.0001
= 6733 years
Answer: After about 9.03 hours the temperature first reach 82 degrees.
Step-by-step explanation:
The sinusoidal function is given by :
![y=A\sin[\omega(x-\alpha)]+C](https://tex.z-dn.net/?f=y%3DA%5Csin%5B%5Comega%28x-%5Calpha%29%5D%2BC)
where, A = amplitude; 
, α= phase shift on the Y-axis and C = midline.
As per given,
Average daily temperature= 
[midline is average of upper and lower limit.]
A= 97-85 = 12
Phase shift: 
Period = 24 hours;
Substitute all values in sinusoidal function, we get
![y=12\sin[\dfrac{\pi}{12}(x-10)]+85](https://tex.z-dn.net/?f=y%3D12%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%2B85)
Put y= 82, we get
![82=12\sin[\dfrac{\pi}{12}(x-10)]+85\\\\\Rightarrow\ -3= 12\sin[\dfrac{\pi}{12}(x-10)]\\\\=\dfrac{-1}{4}= \sin[\dfrac{\pi}{12}(x-10)]\\\\\Rightarrow\ \dfrac{\pi}{12}(x-10)=\sin^{-1}(\dfrac{-1}{4})\\\\\Rightarrow\ x-10=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))\\\\\Rightarrow\ x=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))+10\\\Rightarrow\ x\approx9.03](https://tex.z-dn.net/?f=82%3D12%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%2B85%5C%5C%5C%5C%5CRightarrow%5C%20-3%3D%2012%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%5C%5C%5C%5C%3D%5Cdfrac%7B-1%7D%7B4%7D%3D%20%5Csin%5B%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%5D%5C%5C%5C%5C%5CRightarrow%5C%20%5Cdfrac%7B%5Cpi%7D%7B12%7D%28x-10%29%3D%5Csin%5E%7B-1%7D%28%5Cdfrac%7B-1%7D%7B4%7D%29%5C%5C%5C%5C%5CRightarrow%5C%20x-10%3D%5Cdfrac%7B12%7D%7B%5Cpi%7D%28%5Csin%5E%7B-1%7D%28%5Cdfrac%7B-1%7D%7B4%7D%29%29%5C%5C%5C%5C%5CRightarrow%5C%20x%3D%5Cdfrac%7B12%7D%7B%5Cpi%7D%28%5Csin%5E%7B-1%7D%28%5Cdfrac%7B-1%7D%7B4%7D%29%29%2B10%5C%5C%5CRightarrow%5C%20x%5Capprox9.03)
Hence, After about 9.03 hours the temperature first reach 82 degrees.
Answer:
Step-by-step explanation:
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