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const2013 [10]
4 years ago
5

A restaurant owner made a list of the number of meals ordered last night. She found that 42 people ordered chicken Parmesan, 39

ordered spaghetti and 29 ordered meatballs. Based on this data, what is the experimental probability that the next person will order meatballs?
Mathematics
1 answer:
jasenka [17]4 years ago
5 0

Answer:

29/110

Step-by-step explanation:

There are a total of 110 orders at the restaurant, so that will serve as the denominator. There are 29 meatballs, so that will be the numerator. Combine the two and you get 29/110. Experimental probability is what happens in the experiment like this question. Theoretical probability is "real math" as in 1/3.

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If f(x) = 4^x - 8 and g(x) = 5x + 6, find (f - g)(x)
olganol [36]

Answer:

4^x-5x-14

Step-by-step explanation:

f-g=(4^x-8)-(5x+6)=4^x-8-5x-6=4^x-5x-14

6 0
4 years ago
Read 2 more answers
Two angles are supplementary. One angle is 5degrees° more than six times the other. Find the measure of each angle.
kolbaska11 [484]
Well do you know what a supplementary angles is ?
it is two angles that add up to 180 degrees
6 0
3 years ago
75 people to 25 people
Nat2105 [25]
Percent decrease { (original number - new number) / original number....x 100

percent decrease : (75 - 25) / 75....x 100
                                  50 / 75...x 100
                                  0.666 x 100
                                     66.6% decrease <==not sure if u need it rounded ?
4 0
4 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
Item 4
olga nikolaevna [1]

Answer:

24

Step-by-step explanation:

5 0
3 years ago
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