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andrezito [222]
3 years ago
6

Is the LCM ( least common multiple) of two numbers ( always,sometimes,never) the product of the two numbers?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0
In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b. SOOO, no there can be a lower number then both multiplied by each other.
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Which of the following trigonometric ratios are correct?
den301095 [7]

Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.

  • sinA = opposite/hypotenuse
  • cosA = adjacent/hypotenuse
  • tanA = opposite/adjacent

Now that we know three basic ratio. Let's check each choices!

  • sin50° = d/c

This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.

  • sin50° = c/x

This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.

  • tan50° = d/c

This choice is correct! As ratio states, tanA = opposite/adjacent.

  • tan50° = x/c

This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.

  • cos50° = x/d

This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.

  • cos50° = c/x

This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.

Answer

  • tan50° = d/c
  • cos50° = c/x

Questions can be asked through comment.

Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.

Hope this helps, and Happy Learning! :)

8 0
3 years ago
I need help ASAP , so what’s the answer
aivan3 [116]

The answer would be A.) 1

To find this answer you solve for x. Subtract 3/2 from both sides. This will give you 1/2x = 1/2^x. Then, divide by 1/2 on both sides to get x = 1.

To check this fill in x with 1. Then solve.

  • 1/2 * 1/1 + 3/2 = 2^1
  • 1/2 + 3/2 = 2
  • 4/2 = 2
  • 2 = 2

Thus making 1 the answer. Here's an image to show how I got this. I hope this helps!

6 0
3 years ago
Solve the quadratic equation.<br>m^2/15 -3 = 2​
Radda [10]

The answer is 5 \sqrt{3}

<h3>Explanation :</h3>

\frac{ {m}^{2} }{15}  - 3 = 2

\frac{ {m}^{2} }{15}  = 2  + 3

\frac{ {m}^{2} }{15}  = 5

{m}^{2}  = 5 \times 15

{m}^{2}  = 75

m =  \sqrt{75}

m =  \sqrt{25 \times 3}

m =  \sqrt{25}  \times  \sqrt{3}

m = 5 \sqrt{3}

CMIIW

7 0
3 years ago
Which congruence criteria is met in the following scenario?
Arisa [49]
None because the triangles have different lines
7 0
2 years ago
A mail-order supplier of small electrical parts charges a shipping fee of $8, plus $5 for each pushbutton light switch ordered.
azamat
$38 in total including shipping fee
7 0
3 years ago
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