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dimaraw [331]
3 years ago
11

How to find the distance between two pairs of points

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0
The distance formula<span> is derived from the Pythagorean theorem. To </span>find the distance between two points<span> (x</span>1,y1) and (x2,y2<span>).
 hope that helped

</span>
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Rearrange the equation so U is the independent variable. 4u+8w=−3u+2w
Basile [38]

Answer:

u=-\frac{6}{7} w

Step-by-step explanation:

4u+8w=-3u+2w

Add 3u and -8w on both sides.

4u+3u=2w-8w

Add or subtract like terms.

7u=-6w

Divide 7 on both sides.

7u/7=-6w/7

u=-\frac{6}{7} w

u  is the independent variable now.

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Elsa usually bakes 350 dozen muffins a month. At this rate, how many dozen will she bake in a year ?
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Write 5/z^-3 as a positive exponent
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Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
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