All categories

3 years ago

3/4 + 1/3x = 6 Solve for x

Mathematics

2 answers:

n200080 [17]3 years ago

4 0

$\frac{3}{4} + \frac{1}{3}x = 6$

Multiply both sides of the equation by 12

$9 + 4x = 72$

Move constact to the right-hand side and chancge it's sign.

$4x = 72 - 9$

Subtranct the numbers

$4x = 63$

Divide both sides the equation by 4

Solution:

$x = \frac{63}{4}$

Alternate Form:

$x = 15 \frac{3}{4} x = 15.75$

ehidna [41]3 years ago

3 0

Just subtract 3/4 from both sides that divide 1/3 and x to get your answers

You might be interested in

(46) please help geometry

I am Lyosha [343]

Answer: Rectangle

If you let
P = (0,0)
Q = (0,b)
R = (a,b)
S = (a,0)

you'll be able to find that
PQ is a vertical line with undefined slope
QR is a horizontal line with slope 0
so PQ and QR form a right angle as they are perpendicular lines
You'll find this with the other line pairings as well. We'll have four right angles

3 0

3 years ago

A blank is a number that cannot change its value

lesantik [10]

Answer:

constant

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?

goblinko [34]

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

$A(x) = \frac{f(b)-f(a)}{b-a}$

As per the statement:

$f(x) = x^2-2x-4$

we have to find the average rate of change from x = -1 to x = 4

At x = -1

$f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1$

and

at x = 4

$f(4) = (4)^2-2(4)-4 = 16-8-4 = 4$

Substitute these in [1] we have;

$A(x) = \frac{f(4)-f(-1)}{4-(-1)}$

⇒ $A(x) = \frac{4-(-1)}{4+1}$

⇒ $A(x) = \frac{5}{5}$

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

4 0

3 years ago

Read 2 more answers

Which function is a quadratic function? u(x) = –x 3x2 – 8 v(x) = 2x2 8x3 9x y(x) = x2 3x5 4 z(x) = 7x2 2x3 – 3.

Komok [63]

The function $u(x)=-x+3x^{2} -8$ is a quadratic function due to the highest exponent being 2.

Given functions are:

$u(x)=-x+3x^{2} -8$

$v(x)=2x^{2} +8x^3+9x$

$y(x)=x^{2} +3x^5+4$

$z(x) =7x^{2} +2x^3-3$

<h3>What is a quadratic function?</h3>

A function of the form $f(x)=ax^{2} +bx+c$ with $a\neq 0$ is called a quadratic function means the highest exponent of polynomial should be 2.