Answer is choice B
The ratio of the sides (first to the second) is 11/9 since we divide 22/18 and reduce that fraction
Once we know the scale factor is 11/9, we square it to get (11/9)^2 = 121/81 which is the ratio of the first area to the second area
x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
1:40 because if we think of this just like a fraction

that simplifys down to

and because fraction simplifications are similar (related to each other) we can concur that these would be too.
Enjoy!=)
F(x)=3 domain: negative infinity, positive infinity range: 3
g(x)=x+7 domain: - infinity, + infinity range: - infinity, + infinity
5x + y = -13.....multiply by -3
4x + 3y = -17
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-15x - 3y = 39 (result of multiplying by -3)
4x + 3y = -17
-----------------add
-11x = 22
x = -22/11
x = -2
5x + y = -13
5(-2) + y = -13
-10 + y = -13
y = -13 + 10
y = -3
solution (-2,-3)