This is a little something you have to memorize, but you could derive it from the equation pb = 2π. In the parent function, the b value is 1, so the period, p, is equal to 2π/1 or just 2π.

8 0

3 years ago

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What is the x-intercept of the line with this equation 8x− 1 3 y=16 ? Enter your answer in the box. (, 0)

padilas [110]

8x - 13y = 16

At the x intercept y = 0 so we have:-

8x - 13(0) = 16
8x = 16
x = 16/8 = 2

so the x intercept is at (2,0)

6 0

3 years ago

If a=0 b=0 then complex number a+bi is what type NEED HELP THANKS

notka56 [123]

The answer is a. If there is an i in the equation, then that means “i” is imaginary.

5 0

3 years ago

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A circle has a radius of \sqrt{13}√ 13 square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le

timofeeve [1]

Answer: The equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

Step-by-step explanation: We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

$(x-h)^2+(y-k)^2=r^2.$

In the given circle,

radius, r = √13 units and center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

$(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.$

Thus, the equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

7 0

3 years ago