Question

Help me please, need this done now.

Answer 1

simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Step-by-step explanation:

We need to simplify: $\frac{\sqrt{4}}{\sqrt[3]{4}}$

Solving:

$\frac{\sqrt{4}}{\sqrt[3]{4}}$

We know that √ = 1/2 and ∛=1/3

$\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}$

So, simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Keywords: Solving Exponents  

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