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Fantom [35]
3 years ago
11

Help me please, need this done now.

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Step-by-step explanation:

We need to simplify: \frac{\sqrt{4}}{\sqrt[3]{4}}

Solving:

\frac{\sqrt{4}}{\sqrt[3]{4}}

We know that √ = 1/2 and ∛=1/3

\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

So, simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

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Could someone do all the problems and/or check my work?
MArishka [77]
11. You’ve done it correctly

12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
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13. x^4-x^2-x^2-8=0
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Since y=x^2
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14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath

15. You’re on the right track so I’m just going to continue from where you left off
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Hope this helped :)
8 0
3 years ago
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