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s344n2d4d5 [400]
2 years ago
7

E. To remove a zero pair, drag a box around the pair and click Remove. Remove all of the zero pairs.

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
3 0

Ans = Error

There is no problem for me to solve. Try re-posting the problem and I will try to solve it.

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find the sum of 301+73+27 , mentally, using the associative property of addition. Show how you can use the property to group two
Zolol [24]

Answer:

401

Step-by-step explanation:

301 + 73 + 27

Using the correct order of operations, you would start by adding 301 to 73. Then you'd add 27 to that sum.

Using the associative property of addition, you change the grouping to add 73 and 27 first since that equals 100, and it's easy to add 100 to 301 mentally.

301 + 73 + 27 =

= 301 + (73 + 27)

= 301 + 100

= 410

6 0
3 years ago
What is the value of x in the solution to this system of equations <br> 3x=2y+14<br> y=-6x+18
Radda [10]

Answer:

x=10/3 (or 3.33333333 repeating)

y= -2

Step-by-step explanation:

wayyyy too hard to explain but you can also search photomath and im sure itll give you a good explanation

4 0
3 years ago
5+ x2 – 7х <br><br><br> What is the answer?
PolarNik [594]

Answer:

-5x+5

Step-by-step explanation:

5+2x-7x

Combine like terms:

2x-7x+5\\

which is

-5x+5

Hope this helps :D

7 0
2 years ago
Read 2 more answers
Find the value of x. Round to the nearest tenth.
Nezavi [6.7K]

Answer:

x ≈ 55.6

Step-by-step explanation:

Using the sine ratio in the right triangle

sin20° = \frac{opposite}{hypotenuse} = \frac{19}{x} ( multiply both sides by x )

x × sin20° = 19 ( divide both sides by sin20° )

x = \frac{19}{sin20} ≈ 55.6 ( to the nearest tenth )

7 0
2 years ago
Can somebody help me on 23 and 24, it’s geometry
Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

DS = SE\\3x+10 = 6x-2

Subtracting 10 from both sides

3x+10-10 = 6x-2-10\\3x = 6x-12

subtracting 6x from both sides

3x -6x = 6x-6x-12\\-3x = -12

Dividing both sides by -3

\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4

Now

DS = 3x+10\\= 3(4)+10\\= 12+10\\=22

And

SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25

So

DS = 25+3 = 28

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

4 0
3 years ago
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