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3 years ago

E. To remove a zero pair, drag a box around the pair and click Remove. Remove all of the zero pairs.

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

3 0

Ans = Error

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100 POINTS PLEAS please help

Kamila [148]

Answer:

$\textsf{A)} \quad 5u^3-2u^2+5u+8$

Step-by-step explanation:

Given expression:

$(-2u^3+5u-1)+(7u^3-2u^2+9)$

Remove parentheses:

$\implies -2u^3+5u-1+7u^3-2u^2+9$

Collect like terms:

$\implies -2u^3+7u^3-2u^2+5u-1+9$

Combine like terms:

$\implies 5u^3-2u^2+5u+8$

6 0

1 year ago

Read 2 more answers

Help help help math math math math

Natasha_Volkova [10]

Answer:

x = 15

Explanation:

First, add both equations on one side, and set it equal to 180° because it's supplementary:

2x + 8 + 8x + 22 = 180

combine like terms:

10x + 30 = 180

subtract 30 on both sides of the equation and you end up with:

10x = 150

divide both sides by 10 and you get:

x = 15

3 0

2 years ago

Read 2 more answers

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago

Blake is cutting a piece of rope into fourths if each piece is 16 inches long what is the length of the entire rope

Dovator [93]

The length of the entire rope is 64 inches as when it is cut into four pieces one is 16 therefore when multiplying 16 by four you should get the length of the entire rope which is 64.

8 0

3 years ago

True or False: The proportion of the population that has certain characteristics is the same as the probability that a randomly

atroni [7]

Answer:

True

Step-by-step explanation:

8 0

2 years ago