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jok3333 [9.3K]
3 years ago
6

Write an expression for “the difference of 10 and x.”

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Step-by-step explanation:

The expression for “the difference of 10 and x.”

can be given in two ways:

10 - x

or

x - 10

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X²+y²-6x+14y-1=0<br> and please show your work so I can learn
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Hello there,

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x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

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Type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. find the missing te
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The missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have the roots of a quadratic equation:

5 ± 3i

To find the quadratic equation:

(x - (5+3i))(x - (5-3i))

\rm =x^2+x\left(-\left(5-3i\right)\right)-\left(5+3i\right)x-\left(5+3i\right)\left(-\left(5-3i\right)\right)

= x² -10x + 34

The missing value is 10x

The quadratic equation is:

= x² -10x + 34

Thus, the missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.

Learn more about the complex number here:

brainly.com/question/10251853

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