(12ab)(3t) = (12 · 3)(abt) = 36abt
Answer:
392
Step-by-step explanation:
Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.
Extend lines XQ, YR, YS and XP and mark their intersection as A and B.
Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore
- all angles of the quadrilateral XAYB are right angles
- all sides of XAYB are congruent and equal to 6 + 8 = 14 units.
Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,
we are given
differential equation as

we are given

Firstly, we will find y' , y'' and y'''
those are first , second and third derivative
First derivative is

Second derivative is


Third derivative is


now, we can plug these values into differential equation
and we get

now, we can factor out common terms

we can move that term on right side

now, we can factor out


now, we can set them equal





so, we will get
...............Answer
The answer is c. 1/9.
If x = -2, y = -1, z = 3
then, (-2(-1) -(-1)^2) / 3(3)
(2 - 1)/3(3)
1/9
Answer:
The parent function f(x) is equal to 
The translations is 3 units to the left and 5 units down
Step-by-step explanation:
we have

The vertex of the function h(x) is the point (-3,-5)
we know that the parent function f(x) is equal to

The vertex of the function f(x) is the point (0,0)
so
The rule of the transformation of f(x) to h(x) is equal to
(x,y) -----> (x-3,y-5)
That means ----> The translations is 3 units to the left and 5 units down