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Andre45 [30]
3 years ago
8

What are the roots of the equation x^2+10x=30.

Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0
Idk i'm very confused on this...anyone else?
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Evaluate 8.3p+7.9r when p =3 and r=4. 8.3( ) +7.9( ) = +31.6 help!!!!! ​
Alexandra [31]

Steps: 8.3(3) + 7.9(4) = 31.6

5 0
2 years ago
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The graph represents function 1, and the equation represents function 2:
inessss [21]

Answer:

Option D.

Step-by-step explanation:

The slope of a horizontal line is 0.

It is given that the function 1 is a horizontal line that passing through the y-axis at y = 4.

It means the rate of change of function 1 is 0.

The slope intercept form of a linear function is  1

where, m is slope and b is y-intercept.

The function 2 is  2

On comparing (1) and (2), we get

The rate of change of function 2 is 8.

The difference between rate of change is

The rate of change of function 2 is 8 more than the rate of change of function 1.

Therefore, the correct option is D.

3 0
3 years ago
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Miss Chambers bought 5 pens for $255, if she made a profit of $3 each per pen how much did she sell a pen for?​
Natasha2012 [34]

Answer:

$54

Step-by-step explanation:

First, we calculate the amount she paid for each pen.

$255/5 = $51

She paid $51 for each pen.

She made a profit of $3 per pen, so she sold each pen for $51 + $3 = $54

Answer: $54

6 0
2 years ago
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PLEASE HELP!! GRADE 7 MATHEMATICS!!!
Rzqust [24]
The area of 3x5 face is used 4 times rather then twice
S=94in ^2
5 0
3 years ago
A computer system requires that passwords contain at least one digit. if eight characters are generated at random, and each is e
KIM [24]
Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters]  =  2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8

The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598
6 0
3 years ago
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