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guajiro [1.7K]
3 years ago
6

Two students taking a multiple choice exam with 20 questions and four choices for each question have the same incorrect answer o

n eight of the problems. The probability that student B guesses the same incorrect answer as student A on a particular question is 1/4. If the student is guessing, it is reasonable to assume guesses for different problems are independent. The instructor for the class suspects the students exchanged answers. The teacher decides to present a statistical argument to substantiate the accusation. A possible model for the number of incorrect questions that agree is:
Mathematics
1 answer:
MrRa [10]3 years ago
3 0

Answer:

The Possible model is binomial distribution model.

Step-by-step explanation:

The argument that both students cheated in the exam can be proved by a hypothesis that both the students got the same answers incorrectly.

The same incorrect answers prove that both students have cheated on the test.

Therefore the sample of incorrect answers is, n = 8

Thus, the success probability, P = 0.25

Since the given condition has only two outcomes that are choosing the same answer or not choosing the same answer. Thus, this can be solved by the binomial distribution model.

So, binomial distribution with n = 8 and p = 0 .25.

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Montano1993 [528]

Answer:

the answer is 37.68

Step-by-step explanation:

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C = 2 x 3.14 x 6   the radius is 6 because you divide the diameter by 2 to get the radius which is 6 in thsi case.

2x3.14x6=37.68

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3 years ago
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.
Artist 52 [7]

Answer: 0.0250

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 60.0 minutes.

We know that the uniform distribution is also known as rectangular distribution.

Density function for uniform distribution :f(x)=\dfrac{1}{b-a}

=\dfrac{1}{60-50}=\dfrac{1}{10}

Now, the probability that a given class period runs between 51.25 and 51.5 minutes :-

\int^{51.5}_{51.25}f(x)\ d(x)\\\\ \int^{51.5}_{51.25}\dfrac{1}{10}\ dx\\\\=\dfrac{1}{10} [x]^{51.5}_{51.25}\\\\=\dfrac{1}{10}(51.5-51.25)=0.0250

Hence, the probability that a given class period runs between 51.25 and 51.5 minutes = 0.0250

3 0
3 years ago
Evatuate expreeion of the valube 5 (9+d) - 6
sammy [17]

Answer:

39 + 5d

Step-by-step explanation:

First multiply 5 by 9 and 5 by d then subtract 6 from 45 (which you get from multiplying 5 by 9) and you get 39 and multiply 5 by d so you get 39 + 5d

7 0
3 years ago
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Explain why <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B89%7D%20" id="TexFormula1" title=" \sqrt{89} " alt=" \sqrt{89} " alig
sattari [20]
\sqrt{81}=9 \\ &#10;\sqrt{100}=10

The square root of 81 is 9, the square root of 100 is 10. 89 is between 81 and 100, therefore the square root of 89 must be between 9 and 10.
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3 years ago
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