These questions are all about indirect and direct variation with PV=nRT, the ideal gas equation
Q3.
false, because of PV=nRT, the ideal gas equation if V goes up, P has to go down to equal nRT
Q4. false, if V remains constant, and P and T are constant as moles of gas are added, then something is wrong becse something has to change when stuff is added (V has to go down)
Q5.
PV=nRT
when T and n are constant, (R is the gas constant)
PV=k, aka V=k/P which means inversly proportional
TRUE
Q6.
ggeasy
refer to past question
PV=k
if P is doubled then V has to halve in order to equal k
1/2 times 2=1
volume is halved
Q7. use charles law
V/T=k
so
given
V=4
T= kelvins, so 299
4/299=k
so when temp goes to 22 does V go to 3.95
4/299=3.95/295?
true
because they're equal
Q8
FALSE, must be used in kelvins
T=absolute tempurature in kelvins
Q9
PV=nRT
solve for T
(PV)/(nR)=T
use final volumes and pressures
P=5atm
V=24L
n=1
R=0.082057 atm L/(mol K)
(5atm*24L)/(1mol*0.082057 atm L/mol K)=T
see, if you didn't mess up, the units cancel nicely
T=1462.4
1200 K is closest
Q10
PV/T=constant because moles are constant (supposedly)
V=4L
P=2.08atm
T=275K
so find initial to final is constant
(2.08atm*4L)/(275K)=(Pfinal*2.5L)/(323K)
solve for Pfinal
Pfinal=3.92315 atm
answer is 3.9atm
Merry Christmas
Answer : The correct option is, (C)
Explanation :
A. 
This is synthesis reaction in which the two or more reactant react to give a single product.
B. 
This is combination reaction in which the two reactants combine to form a single product.
C. 
This is a neutralization reaction in which an acid react with a base to give a salt and water as a product.
D. 
This is a double displacement reaction in which the positive cation and negative anion of two reactants exchange their places to give two new products.
Hence, the reaction (C) is a neutralization reaction.
There would be no nobr and it would just be 2
Speed is how fast something is going, velocity is speed and distance, and acceleration is how fast something is speeding up.
Answer:
0.3M
Explanation:
Step 1:
Data obtained from the question. This include the followingb:
Volume of acid (Va) = 90mL
Concentration of acid (Ca) = 0.2M
Volume of base (Vb) = 60mL
Concentration of base (Cb) =....?
Step 2:
The balanced equation for the reaction. This is given below:
HBr + NaOH —> NaBr + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 3:
Determination of the concentration of the base, NaOH.
The concentration of the base can be obtained as follow:
CaVa /CbVb = nA/nB
0.2 x 90 / Cb x 60 = 1
Cross multiply
Cb x 60 = 0.2 x 90
Divide both side by 60
Cb = 0.2 x 90 /60
Cb = 0.3M
Therefore, the concentration of the base, NaOH is 0.3M
