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2 years ago

Work out the volume of the cuboid in cm³

Mathematics

1 answer:

Aliun [14]2 years ago

8 0

Answer:

it is 192000 is got it right

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Wheres the prism to the question?

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3 years ago

Stephen gets paid $4 per hour to babysit his niece. This weekend, he babysat on

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Answer:

The second one, 3 hours

Step-by-step explanation:

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3 years ago

Read 2 more answers

Intergal of 8sin^4(x)dx

Romashka-Z-Leto [24]

$\int\limits8sin^4(x)dx =$

Take the constant out $\int\limits a*f(x)dx=a* \int\limitsf(x)dx$

$= 8 \int\limits sin^4(x)dx$

$\int\limits sin^4(x)dx = - \frac{cos(x)sin^3(x)}{4} = \frac{3}{4} \int\limits sin^2(x)dx$

$= 8( -\frac{cos(x)sin^3(x)}{4}+ \frac{3}{4} \int\limits sin^2(x)dx)
$

Use the following identify : $sin^2(x) = \frac{1-cos(2x)}{2}$

$= 8(- \frac{cos(x)sin^3(x)}{4} + \frac{3}{4} \frac{1}{2}( \int\limits 1 - cos(2x)dx)$

$\int\limits 1dx = x$

$\int\limits cos(2x)dx = \frac{1}{2} sin(2x)$

Apply the sum rule :

$=8(- \frac{cos(x)sin^3(x)}{4} + \frac{3}{4} \frac{1}{2} (x- \frac{1}{2} sin(2x))$

Simplify :

$8( \frac{3}{8} (x- \frac{1}{2} sin(2x)) - \frac{1}{4} sin^3(x)cos(x))$

Therefore add a constant to the solution:

$= 8 ( \frac{3}{8} (x- \frac{1}{2} sin(2x)) - \frac{1}{4} sin^3(x)cos(x))+C$

hope this helps!

3 0

3 years ago

Write an equation that represents the relationship.Please help!

swat32

Answer:

n = r - 2.5

Step-by-step explanation:

We have the following data:

7 4.5

8 5.5

10 7.5

12 9.5

Now, what we will do is what happens if we subtract each one:

7 - 4.5 = 2.5

8 - 5.5 = 2.5

10 - 7.5 = 2.5

12 - 9.5 = 2.5

The difference is always kept constant, therefore the equation would be:

n = r - 2.5

6 0

3 years ago

A(4,9) B(-2,4) find the slope of AB

faust18 [17]

The slope of AB is m =5/6

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3 years ago

Work out the volume of the cuboid in cm³​

Work out the volume of the cuboid in cm³