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Lorico [155]
2 years ago
14

What is the difference between AB and BA.​

Mathematics
2 answers:
coldgirl [10]2 years ago
8 0

Answer:

the difference between \vec{AB}\: and \: \vec{BA} is:

\vec{AB} is equal to opposite of \vec{BA}

mathematically:

\vec{AB}=-\vec{BA}

andriy [413]2 years ago
7 0

Answer:

They are technically the same thing

Step-by-step explanation:

Line BA is the same as line AB. Both pass through the same two points A and B. A line-segment may be also a part of ray. In the figure below, a line segment AB has two end points A and B

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7x-x ............................ .
oee [108]

Answer:

6x

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the sum of the geometric series
Sergio039 [100]
Answer: 2343 / 256

Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
5 0
3 years ago
How do i do this<br>need help if you could do it for me that would be great
Natali [406]
Just follow the cards

8 0
3 years ago
A tournament organizer recorded the number of people in different age groups who participated in the archery tournament. He then
Debora [2.8K]
The total participants were:
30 + 50 + 40 + 10
= 100

Out of which:
30 were 0-19 years old
50 were 20-39 years old
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4 0
3 years ago
Read 2 more answers
What is (3x+5)(x^2+6x+11)
serg [7]

Answer:

\large\boxed{3x^3+23x^2+63x+55}

Step-by-step explanation:

\text{Use FOIL:}\\\\(a+b)(c+d)=ac+ad+bc+bd

(3x+5)(x^2+6x+11)\\\\=(3x)(x^2)+(3x)(6x)+(3x)(11)+(5)(x^2)+(5)(6x)+(5)(11)\\\\=3x^3+18x^2+33x+5x^2+30x+55\qquad\text{combine like terms}\\\\=3x^3+(18x^2+5x^3)+(33x+30x)+55\\\\=3x^3+23x^2+63x+55

3 0
3 years ago
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