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sesenic [268]
3 years ago
10

The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni

ne students as a population.
Complete parts ?(a) through? (c). Student Pulse ??

Perpectual Bempah 64 ??

Megan Brooks 77 ??

Jeff Honeycutt 89 ??

Clarice Jefferson 69 ??

Crystal Kurtenbach 89 ??

Janette Lantka 65 ??

Kevin McCarthy 88 ??

Tammy Ohm 69 ??

Kathy Wojdya 87

(a) Determine the population mean pulse. The population mean pulse is approximately nothing beats per minute. ?(Round to one decimal place as? needed.)

(b) Determine the sample mean pulse of the following two simple random samples of size 3. Sample? 1: StartSet Janette comma Clarice comma Megan EndSet Sample? 2: StartSet Perpectual comma Clarice comma Megan EndSet The mean pulse of sample 1 is approximately nothing beats per minute. ?(Round to one decimal place as? needed.) The mean pulse of sample? 2, is approximately nothing beats per minute. ?(Round to one decimal place as? needed.)

(c) Determine if the means of samples 1 and 2? overestimate, underestimate, or are equal to the population mean. The mean pulse rate of sample 1 ? (underestimates/ is equal to/ overestimates) the population mean. The mean pulse rate of sample 2 (is equal to/ underestimates/ or overestimates) the population mean.
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
3 0

Answer:

a) population\hspace{0.1cm} mean = \frac{64 + 77 + 89 + 69 + 89 + 65 + 88 + 69 + 87}{9} = 77.44

b)sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3

   sample\hspace{0.1cm} mean 2 = \frac{64 + 69 + 77}{3} = 70

c) both the means of the two samples underestimate the population mean.

   the mean pulse rate of sample 1 underestimates the population mean.

   the mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

i) population size, N = 9

a) population\hspace{0.1cm} mean = \frac{64 + 77 + 89 + 69 + 89 + 65 + 88 + 69 + 87}{9} = 77.44

b)sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3

   sample\hspace{0.1cm} mean 2 = \frac{64 + 69 + 77}{3} = 70

c) both the means of the two samples underestimate the population mean.

   the mean pulse rate of sample 1 underestimates the population mean.

   the mean pulse rate of sample 2 underestimates the population mean.

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